• @robinm
    link
    11 year ago

    In C++ integer overflow is UB so this edge case cannot exist

    • @kornel
      link
      31 year ago

      Only signed overflow. size_t is unsigned.

      • @robinm
        link
        1
        edit-2
        1 year ago

        That’s totally right but I thought you were talking about signed numbers since you said “integer overflow”. I forgot that len is usually unsigned in C++.