Neato

    • FizzyOrange
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      6 months ago

      It’s not. In functional languages there’s no special case like this. All if-elses are expressions. It’s far superior. For example how do you do this with Python’s if-else expression?

      let x = if foo {
        let y = bar();
        baz();
        y
      } else {
        z
      }
      
      • nxdefiant@startrek.website
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        6 months ago

        x = foo(y:=bar(), baz(), y) or z should work assuming foo bar and baz are functions being called?

        if this is setting y to the effect of bar() + running baz after, then:

        x = [bar(), baz()][0] or z

        might work

        and if you need y to be defined for later use:

        x = [(y:=bar()), baz()][0] or z

        but thats from memory, not sure if that will even run as written.

        if I get to a real computer I'll try that with an actual if statement instead of a bastardized ternary.
        • FizzyOrange
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          6 months ago

          foo isn’t a function, it’s a bool. But in any case, as you can see the answer is “with terrible hacks”. Python is not a functional language. It is imperative.