• Kogasa
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      4 months ago

      It’s possible to have an equiangular quadrilateral, i.e. whose sides are geodesics (the analogue of “straight line” on a sphere). The Gauss-Bonnet theorem implies their total interior angle is greater than 2pi, so four right angles can’t work.

      Here’s an interactive demo of quadrilaterals on the sphere: https://geogebra.org/m/q83rUj8r

      Notice that each side is a segment of a great circle, i.e. a circle that divides the sphere in half. That’s what it means for a path to be a geodesic on the sphere.