• NeatNit@discuss.tchncs.de
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    3 months ago

    I don’t get it, and the world’s quickest and last comprehensive DDG search didn’t find an explanation either.

    • Kogasa
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      3 months ago

      It’s a reach, but the Fourier transformation of a Schwarz (rapidly decaying) function is also a Schwarz function. Compact support is a strictly stronger condition than Schwarz (the function must eventually decay to 0) but doesn’t have this nice property with respect to Fourier transforms, i.e. the FT of a compactly supported function is Schwarz but not necessarily compactly supported