why I can’t pass my input in foo function

foo() {
	read -r -p "delete $name (default is no) [y/n]?  " choice
	choice="${choice:-n}"
	echo "\$choice: $choice"
}

printf "%s\n" "foo" "bar" "baz" "eggs" "spam" | while read -r name; do
	foo

Expected result:

delete foo (default is no) [y/n]? USER_INPUT
$choice: USER_INPUT
delete bar (default is no) [y/n]? USER_INPUT
$choice: USER_INPUT
# truncated

Actual output:

$choice: bar
$choice: eggs
$choice: n

[!NOTE] Actual output produced without user interaction

  • Korthrun@lemmy.sdf.orgEnglish
    4·
    5 days ago

    Wild, I get syntax error: unexpected end of file when I run your code, so just that alone is very confusing.

    When you’re inside foo here, STDIN is the pipe. Once I fix this syntax error that you somehow dodge and add some extra debugging, you can get a better picture of what’s going on here:

    foo() {
        read -r -p "delete $name (default is no) [y/n]?  " choice
        choice="${choice:-n}"
        echo "\$choice: $choice"
}

printf "%s\n" "foo" "bar" "baz" "eggs" "spam" | while read -r name; do
        printf "Got name '%s'\n" "$name"
        echo calling foo
        foo
done

    Got name 'foo'
calling foo
$choice: bar
Got name 'baz'
calling foo
$choice: eggs
Got name 'spam'
calling foo
$choice: n
    • e55amOPEnglish
      3·
      4 days ago

      Sorry, I’ve dropped done by mistake when I pasted my snippet.

      And thanks for your explanation, but I didn’t fully understand how this happened.