Ha Ha, non-Euclidian geometry go brr. :)
Bye, bye, miss American PI.
This was written by an engineer. They rounded up to 5 for the safety factor.
What kind of problem gives you the formula and all variable to replace? At this point, why not just write 5•10²•10=?
Intro to algebra type stuff to make sure you understand the concept of variables in the first place
Even then, I would want them to leave π in the problem itself. That would be much better for this exercise - teaching that you report “exact” values with π still in them.
Eg, if I rewrote this problem, I would expect an answer of 1000π.
Pi= 5 in this teachers reality. Circles must look wonky.
…fractal circumferences can be whatever length you want for any given mean radius…
It makes it easy to do the math in your head without a calculator. But still , just tossing out pi=5 is not the way to go about creating these problems.
Cause reading comprehension is part of the test. Lots of kids will be able to solve that equation, but there’s a bunch who can’t understand it if it’s presented this way.
Honestly here they should have done “round pi to two decimal places” or smth.One written in Comic fucking Sans
It’s official, the observable universe is ~3 times larger!
It went to far and Beck.
Man the Americans… everyone knows that π=-10
Nah, π = 3.2.
the Speaker accepted another member’s recommendation to refer the bill to the Committee on Swamplands, where the bill could “find a deserved grave”
Lmao
What in the idiocracy
deleted by creator
Think of the Loch Ness Monster and use tree fiddy and you’re much closer
Ah said MONSTAH!!
Calculator not allowed test probably
3.14 would be easy enough to solve this one. r^2*h resolves to 1000, so V would be 3140.
I didn’t get to use a calculator IN CLASS until late in my bachelor studies — forget about using them for tests. In a world with Chatgpt we need to teach in a more sterile environment or standards are going to swing into the ditch. My friend who is a grade school teacher has told me some stories that would make your ears bleed.
Even if so, the other factors are both 10. How hard can it be…
Americans are more fat so they need bigger Pi to keep geometry in touch with reality.
I remember when Pi was monetized, that sounds like Pi Common, only $9.99/mo for 0 significant digits.
Ah yes. I have heard about that.
American Pi.
Believe it or not, there is precedent for this.
“Now this is a fucked up situation.”
Round Up.
round
heh
Sick burn. Especially from a Belgian! Waddle waddle
I’m an American. I weigh about 140 lbs (63.5 kg). I’m about 5.75 ft (1.75 m) tall. Am I fat?
Fat? No, but dumb enough to understand my phrase as “each and every without a single exception”. Dumb as an American.
I’m American. I got 80% on my IQ test am I dumb? That’s a GPA of 3.0.
I’m not the one making dumb generalizations. Fuck off with your stereotypes.
You’re literally a walking stereotype, incredible!
Well, stereotypes are lazy humor, and I’m lazy & my life is a joke - so you’ve got me there.
Fair enough
Yes, you should lose 100lbs. Just look at people who were forced on a diet. They were just bones because they had nothing to eat but flour and water. You got to go for the emaciated look.
Manlet. Barely better than fatass.
Assigning a value of 5 to pi, although ludicrous IRL, doesn’t affect the problem. Plug the values into the equation and it will still give an answer that’s correct in context.
For the benefit of doubt, maybe the test is from an alternate dimension that doesn’t use euclidean space.
Possible. I mean, electricity could actually be run by ghosts, but there’s no need for fanciful explanations when a mundane one is right there.
I’ve been there, I think, but it was really difficult to triangulate my location and confirm
That’s because you were supposed to rhombusulate, not triangulate.
If the goal is to avoid calculations with decimal places, why not just leave Pi in the result?
That would work too.
I wish they would have used 22/7 for pi and 7 for the radius or height
Do cylinders even exist in metrics where pi = 5 ?
Technically no, because pi equals pi not 5. But you can approximate its value as 3 or 5 or whatever you want, knowing it’s not exact and that your result will only be an approximation. I mean you could also ask how long light takes to reach us from Alpha Centauri if the speed of light is 1000 mph. It’s not, but if you make that a condition of the problem you can do the calculation just fine.
Yes. The 3d shape existence is not affected by changing pi values
Cause it’s just a (n-1)-dimensional ball extruded along the remaining axis, or do all 3d shapes exist on (nearly) all 3d metrics?
It’s clearly just saying that the surfaces on which the ends of the cylinder lie are metric spaces with distances defined using Chebyshev or Taxicab metrics based on pentagonal tilings of the parabolic plane so the ratio of a circle’s circumference to diameter is 5.
Since it’s a cylinder we assume the vertical dimension is Euclidean and voila the math checks out geometrically.
Whoa, amazing!
Astrology is so cool
You know what’s even cooler?
G E O L O G Y !!
Geology rocks
