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Is that Bill Gates?
Yep, the poorer of the two dudes playing lol
sucks to be him
Well, you’ve got 1. And -1. And sqrt(-1). And the unit pseudoscalars of the Clifford algebras for every number of dimensions.
So there are a countably infinite number of solutions. Can anyone find a bigger set? Something with an uncountably infinite set of solutions?
There’s only 2. sqrt(-1) isn’t a solution. There are at most 2 over any integral domain.
not sure I’m following. there are only two solutions to this. the equation is essentially:
x² -1 = 0 x² = 1 x = ±√1 x = ±1 => x = 1, x = -1supposing x was √-1:
(√-1)² -1 = 0 -1 -1 = 0 -2 = 0therefore we can certainly conclude that x ≠ √-1
