Regression in signal handler.
This vulnerability is exploitable remotely on glibc-based Linux systems, where syslog() itself calls async-signal-unsafe functions (for example, malloc() and free()): an unauthenticated remote code execution as root, because it affects sshd’s privileged code, which is not sandboxed and runs with full privileges.
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8.5p1 <= OpenSSH < 9.8p1 is vulnerable
what does that mean? I don’t understand multiple signs in the same sentence and what is the significance of having “OpenSSH” in the middle?
You can read them as separate statements with the middle repeated and a logical AND between them:
If (8.5p1 <= your OpenSSH version) AND (your OpenSSH version < 9.8p1) Then you are vulnerable
It’s the same as saying if your OpenSSH version is between these two versions (including 8.5p1, but not 9.8p1), then you are vulnerable
I don’t get it… wouldn’t everything < 9.8p1 already include <= 8.5p1? So why is it even necessary to mention?
For an integer,
4 < x < 6x has to be 5. It’s the only value that satisfies all sides of the equation.
You are deriving a set of values foropen sshthat satisfies all sides of the equation.I think it’s more of a mathematical representation than programming representation (I mean, I don’t know of a language that would accept that syntax).
Certainly psuedocode would have quick statements like thisseems to work fine in C and I can find quite a bit of examples of it being used actually
Oh, I can’t find any examples. What are you searching for?
The closest I can find is an old hlsl offhand comment showing the syntax in isolation, but no example.
https://stackoverflow.com/a/29689866
Because this is a regression and this particular issue was introduced in 8.5p1. So it only affects versions newer than that, up until when it was fixed in 9.8p1.
