Day 3: Mull It Over
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FAQ
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I also used Go - my solution for part 1 was essentially identical to yours. I went a different route for part 2 that I think ended up being simpler though.
I just prepended
do()
anddon't()
to the original regex with a|
, that way it captured all 3 in order and I just looped through all the matches once and toggled theisEnabled
flag accordingly.Always interesting to see how other people tackle the same problem!
Part 2 Code
func part2() { filePath := "input.txt" file, _ := os.Open(filePath) defer file.Close() pattern := regexp.MustCompile(`do\(\)|don't\(\)|mul\((\d{1,3}),(\d{1,3})\)`) productSum := 0 isEnabled := true scanner := bufio.NewScanner(file) for scanner.Scan() { line := scanner.Text() matches := pattern.FindAllStringSubmatch(line, -1) for _, match := range matches { if match[0] == "do()" { isEnabled = true } else if match[0] == "don't()" { isEnabled = false } else if isEnabled && len(match) == 3 { n, _ := strconv.Atoi(match[1]) m, _ := strconv.Atoi(match[2]) productSum += n * m } } } fmt.Println("Total: ", productSum) }
Honestly this is soo much better, I’m not proud of my code at all haha. Thanks for sharing, definitely adding that | to my bag of tricks