Day 4: Ceres Search
Megathread guidelines
- Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
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FAQ
- What is this?: Here is a post with a large amount of details: https://programming.dev/post/6637268
- Where do I participate?: https://adventofcode.com/
- Is there a leaderboard for the community?: We have a programming.dev leaderboard with the info on how to join in this post: https://programming.dev/post/6631465
This one was a little bit of a pain. I loved it.
TypeScript
Solution
import { AdventOfCodeSolutionFunction } from "./solutions"; enum Direction { UP, UP_RIGHT, RIGHT, BOTTOM_RIGHT, BOTTOM, BOTTOM_LEFT, LEFT, UP_LEFT, }; const ALL_DIRECTIONS = [ Direction.RIGHT, Direction.BOTTOM_RIGHT, Direction.BOTTOM, Direction.BOTTOM_LEFT, Direction.LEFT, Direction.UP_LEFT, Direction.UP, Direction.UP_RIGHT, ]; const check_coords = (grid: Array<Array<string>>, x: number, y: number) => { return y >= grid.length || y < 0 || x >= grid[y].length || x < 0 } const search_direction = (grid: Array<Array<string>>, x: number, y: number, direction: Direction, find: Array<string>) => { // exit conditions // no more to find if (find.length == 0) return 1; // found the end // invalid coords if (check_coords(grid, x, y)) return 0; // make new mutable list const newFind = [...find]; const searchChar = newFind.shift(); // wrong character if (grid[y][x] !== searchChar) return 0; switch (direction) { case Direction.UP: return search_direction(grid, x, y + 1, direction, newFind); case Direction.UP_RIGHT: return search_direction(grid, x + 1, y + 1, direction, newFind); case Direction.RIGHT: return search_direction(grid, x + 1, y, direction, newFind); case Direction.BOTTOM_RIGHT: return search_direction(grid, x + 1, y - 1, direction, newFind); case Direction.BOTTOM: return search_direction(grid, x, y - 1, direction, newFind); case Direction.BOTTOM_LEFT: return search_direction(grid, x - 1, y - 1, direction, newFind); case Direction.LEFT: return search_direction(grid, x - 1, y, direction, newFind); case Direction.UP_LEFT: return search_direction(grid, x - 1, y + 1, direction, newFind); default: return 0; } } const part_1_search = (grid: Array<Array<string>>, x: number, y: number, find: Array<string>) => { return ALL_DIRECTIONS.reduce<number>( (instances, direction) => instances + search_direction(grid, x, y, direction, find), 0 ); } const part_2_search = (grid: Array<Array<string>>, x: number, y: number, find: Array<string>) => { return ( search_direction(grid, x - 1, y + 1, Direction.BOTTOM_RIGHT, find) + search_direction(grid, x + 1, y + 1, Direction.BOTTOM_LEFT, find) + search_direction(grid, x - 1, y - 1, Direction.UP_RIGHT, find) + search_direction(grid, x + 1, y - 1, Direction.UP_LEFT, find) ) == 2 ? 1 : 0; } export const solution_4: AdventOfCodeSolutionFunction = (input) => { const grid = input.split("\n").map(st => st.trim()).map(v => v.split("")); let part_1 = 0; let part_2 = 0; const find_1 = "XMAS".split(""); const find_2 = "MAS".split(""); for (let y = 0; y < grid.length; y++) { for (let x = 0; x < grid[y].length; x++) { part_1 += part_1_search(grid, x, y, find_1); part_2 += part_2_search(grid, x, y, find_2); } } return { part_1, part_2, }; }
Felt like this code quality is better than what I usually output :)
J
Unsurprisingly this is the kind of problem that J is really good at. The dyadic case (table) of the adverb
/
is doing all the heavy lifting here: it makes a higher rank tensor by traversing items of the specified rank on each side and combining them according to the remaining frame of each side’s shape. The hard part is arranging the arguments so that your resulting matrix has its axes in the correct order.data_file_name =: '4.data' NB. cutopen yields boxed lines, so unbox them and ravel items to make a letter matrix grid =: ,. > cutopen fread data_file_name NB. pad the grid on every side with #'XMAS' - 1 spaces hpadded_grid =: ((' ' & ,) @: (, & ' '))"1 grid padded_grid =: (3 1 $ ' ') , hpadded_grid , (3 1 $ ' ') NB. traversal vectors directions =: 8 2 $ 1 0 1 1 0 1 _1 1 _1 0 _1 _1 0 _1 1 _1 NB. rpos cpos matches rdir cdir if the string starting at rpos cpos in NB. direction rdir cdir is the string we want matches =: 4 : 0 */ ,'XMAS' -: padded_grid {~ <"1 x +"1 y *"1 0 i. 4 )"1 positions =: (3 + i. 0 { $ grid) ,"0/ (3 + i. 1 { $ grid) result1 =: +/, positions matches/ directions NB. pairs of traversal vectors x_directions =: 4 2 2 $ 1 1 _1 1 1 1 1 _1 _1 _1 _1 1 _1 _1 1 _1 NB. rpos cpos x_matches 2 2 $ rdir1 cdir1 rdir2 cdir2 if there is an 'A' at NB. rpos cpos and the string in each of dir1 and dir2 centered at rpos cpos NB. is the string we want x_matches =: 4 : 0 NB. (2 2 $ rdir1 cdir1 rdir2 cdir2) *"1 0/ (_1 + i.3) yields a matrix NB. 2 3 $ (_1 * dir1) , (0 * dir1) , (1 * dir1) followed by the same for dir2 */ ,'MAS' -:"1 padded_grid {~ <"1 x +"1 y *"1 0/ _1 + i. 3 )"1 2 result2 =: +/, positions x_matches/ x_directions
Go
Just a bunch of ifs and bounds checking. Part 2 was actually simpler.
Code
func part1(W [][]rune) { m := len(W) n := len(W[0]) xmasCount := 0 for i := 0; i < m; i++ { for j := 0; j < n; j++ { if W[i][j] != 'X' { continue } if j < n-3 && W[i][j+1] == 'M' && W[i][j+2] == 'A' && W[i][j+3] == 'S' { // Horizontal left to right xmasCount++ } if j >= 3 && W[i][j-1] == 'M' && W[i][j-2] == 'A' && W[i][j-3] == 'S' { // Horizontal right to left xmasCount++ } if i < m-3 && W[i+1][j] == 'M' && W[i+2][j] == 'A' && W[i+3][j] == 'S' { // Vertical up to down xmasCount++ } if i >= 3 && W[i-1][j] == 'M' && W[i-2][j] == 'A' && W[i-3][j] == 'S' { // Vertical down to up xmasCount++ } if j < n-3 && i < m-3 && W[i+1][j+1] == 'M' && W[i+2][j+2] == 'A' && W[i+3][j+3] == 'S' { // Diagonal left to right and up to down xmasCount++ } if j >= 3 && i < m-3 && W[i+1][j-1] == 'M' && W[i+2][j-2] == 'A' && W[i+3][j-3] == 'S' { // Diagonal right to left and up to down xmasCount++ } if j < n-3 && i >= 3 && W[i-1][j+1] == 'M' && W[i-2][j+2] == 'A' && W[i-3][j+3] == 'S' { // Diagonal left to right and down to up xmasCount++ } if j >= 3 && i >= 3 && W[i-1][j-1] == 'M' && W[i-2][j-2] == 'A' && W[i-3][j-3] == 'S' { // Diagonal right to left and down to up xmasCount++ } } } fmt.Println(xmasCount) } func part2(W [][]rune) { m := len(W) n := len(W[0]) xmasCount := 0 for i := 0; i <= m-3; i++ { for j := 0; j <= n-3; j++ { if W[i+1][j+1] != 'A' { continue } if W[i][j] == 'M' && W[i][j+2] == 'M' && W[i+2][j] == 'S' && W[i+2][j+2] == 'S' { xmasCount++ } else if W[i][j] == 'M' && W[i][j+2] == 'S' && W[i+2][j] == 'M' && W[i+2][j+2] == 'S' { xmasCount++ } else if W[i][j] == 'S' && W[i][j+2] == 'S' && W[i+2][j] == 'M' && W[i+2][j+2] == 'M' { xmasCount++ } else if W[i][j] == 'S' && W[i][j+2] == 'M' && W[i+2][j] == 'S' && W[i+2][j+2] == 'M' { xmasCount++ } } } fmt.Println(xmasCount) } func main() { file, _ := os.Open("input.txt") defer file.Close() scanner := bufio.NewScanner(file) var W [][]rune for scanner.Scan() { line := scanner.Text() W = append(W, []rune(line)) } part1(W) part2(W) }
Raku
Oof, my struggle to make custom index walking paths for part 1 did not pay off for part 2.
Solution
sub MAIN($input) { my $file = (open $input).slurp; my @grid is List = $file.lines».comb».list; my @transposedGrid is List = [Z] @grid; my @reversedGrid is List = @grid».reverse; my @transposedReversedGrid is List = @transposedGrid».reverse; my @horizontalScanRows is List = generateScanHorizontal(@grid); my @transposedHorizontalScanRows is List = generateScanHorizontal(@transposedGrid); my @part-one-counts = []; @part-one-counts.push(count-xmas(@grid, @horizontalScanRows)); # Right @part-one-counts.push(count-xmas(@transposedGrid, @transposedHorizontalScanRows)); # Down @part-one-counts.push(count-xmas(@reversedGrid, @horizontalScanRows)); # Left @part-one-counts.push(count-xmas(@transposedReversedGrid, @transposedHorizontalScanRows)); # Up my @diagonalScanRows is List = generateScanDiagonal(@grid); my @transposedDiagonalScanRows is List = generateScanDiagonal(@transposedGrid); @part-one-counts.push(count-xmas(@grid, @diagonalScanRows)); # Down Right @part-one-counts.push(count-xmas(@grid, @diagonalScanRows».reverse)); # Up Left @part-one-counts.push(count-xmas(@reversedGrid, @diagonalScanRows)); # Down Left @part-one-counts.push(count-xmas(@reversedGrid, @diagonalScanRows».reverse)); # Up Right my $part-one-solution = @part-one-counts.sum; say "part 1: $part-one-solution"; my @part-two-counts = []; @part-two-counts.push(countGridMatches(@grid, (<M . S>,<. A .>,<M . S>))); @part-two-counts.push(countGridMatches(@grid, (<S . S>,<. A .>,<M . M>))); @part-two-counts.push(countGridMatches(@grid, (<S . M>,<. A .>,<S . M>))); @part-two-counts.push(countGridMatches(@grid, (<M . M>,<. A .>,<S . S>))); my $part-two-solution = @part-two-counts.sum; say "part 2: $part-two-solution"; } sub count-xmas(@grid, @scanRows) { my $xmas-count = 0; for @scanRows -> @scanRow { my $xmas-pos = 0; for @scanRow -> @pos { my $char = @grid[@pos[0]][@pos[1]]; if "X" eq $char { $xmas-pos = 1; }elsif <X M A S>[$xmas-pos] eq $char { if $xmas-pos == 3 { $xmas-pos = 0; $xmas-count += 1; } else { $xmas-pos += 1; } } else { $xmas-pos = 0; } } } return $xmas-count; } sub generateScanHorizontal(@grid) { # Horizontal my $rows = @grid.elems; my $cols = @grid[0].elems; my @scanRows = (); for 0..^$rows -> $row { my @scanRow = (); for 0..^$cols -> $col { @scanRow.push(($row, $col)); } @scanRows.push(@scanRow); } return @scanRows.List».List; } sub generateScanDiagonal(@grid) { # Down-right diagonal my $rows = @grid.elems; my $cols = @grid[0].elems; my @scanRows = (); for 0..^($rows + $cols - 1) -> $diag { my @scanRow = (); my $starting-row = max(-$cols + $diag + 1, 0); my $starting-col = max($rows - $diag - 1, 0); my $diag-len = min($rows - $starting-row, $cols - $starting-col); for 0..^$diag-len -> $diag-pos { @scanRow.push(($starting-row + $diag-pos, $starting-col + $diag-pos)); } @scanRows.push(@scanRow); } return @scanRows.List».List; } sub countGridMatches(@grid, @needle) { my $count = 0; for 0..(@grid.elems - @needle.elems) -> $top { TOP-LEFT: for 0..(@grid[$top].elems - @needle[0].elems) -> $left { for 0..^@needle.elems -> $row-offset { for 0..^@needle[$row-offset].elems -> $col-offset { my $needle-char = @needle[$row-offset][$col-offset]; next if $needle-char eq "."; next TOP-LEFT if $needle-char ne @grid[$top+$row-offset][$left+$col-offset]; } } $count += 1; } } return $count; }
C#
namespace Day04; static class Program { public record struct Point(int Row, int Col); static void Main(string[] args) { var sample = File.ReadAllLines("sample.txt"); var data = File.ReadAllLines("data.txt"); Console.WriteLine($"Part 1 (sample): {SolvePart1(sample)}"); Console.WriteLine($"Part 1 (data): {SolvePart1(data)}"); Console.WriteLine($"Part 2 (sample): {SolvePart2(sample)}"); Console.WriteLine($"Part 2 (data): {SolvePart2(data)}"); } private static readonly string Search = "XMAS"; private static readonly Func<Point, Point>[] DirectionalMoves = { p => new Point(p.Row + 1, p.Col), p => new Point(p.Row + 1, p.Col + 1), p => new Point(p.Row, p.Col + 1), p => new Point(p.Row - 1, p.Col + 1), p => new Point(p.Row - 1, p.Col), p => new Point(p.Row - 1, p.Col - 1), p => new Point(p.Row, p.Col - 1), p => new Point(p.Row + 1, p.Col - 1), }; private static readonly Func<Point, Point>[] ForwardSlashMoves = { p => new Point(p.Row - 1, p.Col - 1), p => new Point(p.Row + 1, p.Col + 1), }; private static readonly Func<Point, Point>[] BackSlashMoves = { p => new Point(p.Row + 1, p.Col - 1), p => new Point(p.Row - 1, p.Col + 1), }; static long SolvePart1(string[] data) { return Enumerable .Range(0, data.Length) .SelectMany(row => Enumerable.Range(0, data[row].Length) .Select(col => new Point(row, col))) .Where(p => IsMatch(data, p, Search[0])) .Sum(p => DirectionalMoves .Count(move => DeepMatch(data, move(p), move, Search, 1))); } static long SolvePart2(string[] data) { return Enumerable .Range(0, data.Length) .SelectMany(row => Enumerable.Range(0, data[row].Length) .Select(col => new Point(row, col))) .Where(p => IsMatch(data, p, 'A')) .Count(p => CheckDiagonalMoves(data, p, ForwardSlashMoves) && CheckDiagonalMoves(data, p, BackSlashMoves)); } static bool CheckDiagonalMoves(string[] data, Point p, Func<Point, Point>[] moves) => (IsMatch(data, moves[0](p), 'S') && IsMatch(data, moves[1](p), 'M')) || (IsMatch(data, moves[0](p), 'M') && IsMatch(data, moves[1](p), 'S')); static bool DeepMatch(string[] data, Point p, Func<Point, Point> move, string search, int searchIndex) => (searchIndex >= search.Length) ? true : (!IsMatch(data, p, search[searchIndex])) ? false : DeepMatch(data, move(p), move, search, searchIndex + 1); static bool IsMatch(string[] data, Point p, char searchChar) => IsInBounds(data, p) && (data[p.Row][p.Col] == searchChar); static bool IsInBounds(string[] data, Point p) => (p.Row >= 0) && (p.Col >= 0) && (p.Row < data.Length) && (p.Col < data[0].Length); }
Kotlin
fun part1(input: String): Int { return countWordOccurrences(input.lines()) } fun part2(input: String): Int { val grid = input.lines().map(String::toList) var count = 0 for (row in 1..grid.size - 2) { for (col in 1..grid[row].size - 2) { if (grid[row][col] == 'A') { count += countCrossMatch(grid, row, col) } } } return count } private fun countCrossMatch(grid: List<List<Char>>, row: Int, col: Int): Int { val surroundingCorners = listOf( grid[row - 1][col - 1], // upper left grid[row - 1][col + 1], // upper right grid[row + 1][col - 1], // lower left grid[row + 1][col + 1], // lower right ) // no matches: // M S S M // A A // S M M S return if (surroundingCorners.count { it == 'M' } == 2 && surroundingCorners.count { it == 'S' } == 2 && surroundingCorners[0] != surroundingCorners[3] ) 1 else 0 } private fun countWordOccurrences(matrix: List<String>): Int { val rows = matrix.size val cols = if (rows > 0) matrix[0].length else 0 val directions = listOf( Pair(0, 1), // Horizontal right Pair(1, 0), // Vertical down Pair(1, 1), // Diagonal down-right Pair(1, -1), // Diagonal down-left Pair(0, -1), // Horizontal left Pair(-1, 0), // Vertical up Pair(-1, -1), // Diagonal up-left Pair(-1, 1) // Diagonal up-right ) fun isWordAt(row: Int, col: Int, word: String, direction: Pair<Int, Int>): Boolean { val (dx, dy) = direction for (i in word.indices) { val x = row + i * dx val y = col + i * dy if (x !in 0 until rows || y !in 0 until cols || matrix[x][y] != word[i]) { return false } } return true } var count = 0 for (row in 0 until rows) { for (col in 0 until cols) { for (direction in directions) { if (isWordAt(row, col, "XMAS", direction)) { count++ } } } } return count }
Uiua
Just part1 for now as I need to walk the dog :-)
[edit] Part 2 now added, and a nicer approach than Part 1 in my opinion, if you’re able to keep that many dimensions straight in your head :-)
[edit 2] Tightened it up a bit more.
Grid ← ⊜∘⊸≠@\n "MMMSXXMASM\nMSAMXMSMSA\nAMXSXMAAMM\nMSAMASMSMX\nXMASAMXAMM\nXXAMMXXAMA\nSMSMSASXSS\nSAXAMASAAA\nMAMMMXMMMM\nMXMXAXMASX" ≡⍉⍉×⇡4¤[1_0 0_1 1_1 1_¯1] # Use core dirs to build sets of 4-offsets. ↯∞_2⇡△ Grid # Get all possible starting points. &p/+♭⊞(+∩(≍"XMAS")⇌.⬚@.⊡:Grid≡+¤) # Part 1. Join the two into a table, use to pick 4-elements, check, count. Diags ← [[¯. 1_1] [¯. 1_¯1]] BothMas ← /×≡(+∩(≍"MS")⇌.)⬚@.⊡≡+Diags¤¤ # True if both diags here are MAS. &p/+≡BothMas⊚="A"⟜¤Grid # Part 2. For all "A"s in grid, check diags, count where good.
I’m not even sure how to write most of these characters
The operators have all got ascii names you can type, and the formatter converts them to the symbols. It’s a bit odd but really worthwhile, as you get access to the powerful array handling functionality that made solving today’s challenges so much more straightforward than in other languages.
It looks quite functional indeed
C
What can I say, bunch of for loops! I add a 3 cell border to avoid having to do bounds checking in the inner loops.
Code
#include "common.h" #define GZ 146 int main(int argc, char **argv) { static char g[GZ][GZ]; static const char w[] = "XMAS"; int p1=0,p2=0, x,y, m,i; if (argc > 1) DISCARD(freopen(argv[1], "r", stdin)); for (y=3; y<GZ && fgets(g[y]+3, GZ-3, stdin); y++) ; for (y=3; y<GZ-3; y++) for (x=3; x<GZ-3; x++) { for (m=1,i=0; i<4; i++) {m &= g[y+i][x]==w[i];} p1+=m; for (m=1,i=0; i<4; i++) {m &= g[y-i][x]==w[i];} p1+=m; for (m=1,i=0; i<4; i++) {m &= g[y][x+i]==w[i];} p1+=m; for (m=1,i=0; i<4; i++) {m &= g[y][x-i]==w[i];} p1+=m; for (m=1,i=0; i<4; i++) {m &= g[y+i][x+i]==w[i];} p1+=m; for (m=1,i=0; i<4; i++) {m &= g[y-i][x-i]==w[i];} p1+=m; for (m=1,i=0; i<4; i++) {m &= g[y+i][x-i]==w[i];} p1+=m; for (m=1,i=0; i<4; i++) {m &= g[y-i][x+i]==w[i];} p1+=m; p2 += g[y+1][x+1]=='A' && ((g[y][x] =='M' && g[y+2][x+2]=='S') || (g[y][x] =='S' && g[y+2][x+2]=='M')) && ((g[y+2][x]=='M' && g[y][x+2] =='S') || (g[y+2][x]=='S' && g[y][x+2] =='M')); } printf("04: %d %d\n", p1, p2); }
python
solution
import aoc def setup(): return (aoc.get_lines(4, padded=(True, '.', 3)), 0) def one(): lines, acc = setup() for row, l in enumerate(lines): for col, c in enumerate(l): if c == 'X': w = l[col - 3:col + 1] e = l[col:col + 4] n = c + lines[row - 1][col] + \ lines[row - 2][col] + lines[row - 3][col] s = c + lines[row + 1][col] + \ lines[row + 2][col] + lines[row + 3][col] nw = c + lines[row - 1][col - 1] + \ lines[row - 2][col - 2] + lines[row - 3][col - 3] ne = c + lines[row - 1][col + 1] + \ lines[row - 2][col + 2] + lines[row - 3][col + 3] sw = c + lines[row + 1][col - 1] + \ lines[row + 2][col - 2] + lines[row + 3][col - 3] se = c + lines[row + 1][col + 1] + \ lines[row + 2][col + 2] + lines[row + 3][col + 3] for word in [w, e, n, s, nw, ne, sw, se]: if word in ['XMAS', 'SAMX']: acc += 1 print(acc) def two(): lines, acc = setup() for row, l in enumerate(lines): for col, c in enumerate(l): if c == 'A': l = lines[row - 1][col - 1] + c + lines[row + 1][col + 1] r = lines[row + 1][col - 1] + c + lines[row - 1][col + 1] if l in ['MAS', 'SAM'] and r in ['MAS', 'SAM']: acc += 1 print(acc) one() two()
Haskell
Popular language this year :)
I got embarrassingly stuck on this one trying to be clever with list operations. Then I realized I should just use an array…
import Data.Array.Unboxed (UArray) import Data.Array.Unboxed qualified as A import Data.Bifunctor readInput :: String -> UArray (Int, Int) Char readInput s = let rows = lines s n = length rows in A.listArray ((1, 1), (n, n)) $ concat rows s1 `eq` s2 = s1 == s2 || s1 == reverse s2 part1 arr = length $ filter isXmas $ concatMap lines $ A.indices arr where isXmas ps = all (A.inRange $ A.bounds arr) ps && map (arr A.!) ps `eq` "XMAS" lines p = [take 4 $ iterate (bimap (+ di) (+ dj)) p | (di, dj) <- [(1, 0), (0, 1), (1, 1), (1, -1)]] part2 arr = length $ filter isXmas innerPoints where innerPoints = let ((i1, j1), (i2, j2)) = A.bounds arr in [(i, j) | i <- [i1 + 1 .. i2 - 1], j <- [j1 + 1 .. j2 - 1]] isXmas p = up p `eq` "MAS" && down p `eq` "MAS" up (i, j) = map (arr A.!) [(i + 1, j - 1), (i, j), (i - 1, j + 1)] down (i, j) = map (arr A.!) [(i - 1, j - 1), (i, j), (i + 1, j + 1)] main = do input <- readInput <$> readFile "input04" print $ part1 input print $ part2 input
Rust
One of those with running through tricky grid indices. The vector types from the euclid crate helped in dealing with positions.
Code
use euclid::{vec2, default::*}; fn count_xmas(grid: &[&[u8]], pos: (usize, usize)) -> u32 { if grid[pos.1][pos.0] != b'X' { return 0 } let bounds = Rect::new(Point2D::origin(), Size2D::new(grid[0].len() as i32, grid.len() as i32)); const DIRS: [Vector2D<i32>; 8] = [ vec2(1, 0), vec2(-1, 0), vec2(0, 1), vec2(0, -1), vec2(1, 1), vec2(1, -1), vec2(-1, 1), vec2(-1, -1), ]; let mut count = 0; for dir in DIRS { let mut cur = Point2D::from(pos).to_i32(); let mut found = true; for letter in [b'M', b'A', b'S'] { cur += dir; if !bounds.contains(cur) || grid[cur.y as usize][cur.x as usize] != letter { found = false; break } } if found { count += 1; } } count } fn part1(input: String) { let grid = input.lines().map(|l| l.as_bytes()).collect::<Vec<_>>(); let count = (0..grid.len()).map(|y| { (0..grid[y].len()).map(|x| count_xmas(&grid, (x, y))).sum::<u32>() }) .sum::<u32>(); println!("{count}"); } fn is_x_mas(grid: &[&[u8]], pos: (usize, usize)) -> bool { if grid[pos.1][pos.0] != b'A' { return false } const DIRS: [Vector2D<i32>; 4] = [vec2(1, -1), vec2(1, 1), vec2(-1, 1), vec2(-1, -1)]; let pos = Point2D::from(pos).to_i32(); (0..4).any(|d| { let m_pos = [pos + DIRS[d], pos + DIRS[(d + 1) % 4]]; // 2 adjacent positions of M let s_pos = [pos + DIRS[(d + 2) % 4], pos + DIRS[(d + 3) % 4]]; // others S m_pos.iter().all(|p| grid[p.y as usize][p.x as usize] == b'M') && s_pos.iter().all(|p| grid[p.y as usize][p.x as usize] == b'S') }) } fn part2(input: String) { let grid = input.lines().map(|l| l.as_bytes()).collect::<Vec<_>>(); let count = (1..grid.len() - 1).map(|y| { (1..grid[y].len() - 1).filter(|&x| is_x_mas(&grid, (x, y))).count() }) .sum::<usize>(); println!("{count}"); } util::aoc_main!();
(also on github)
I struggled a lot more when doing list slices that I would’ve liked to
Haskell
import Data.List qualified as List collectDiagonal :: [String] -> Int -> Int -> String collectDiagonal c y x | length c > y && length (c !! y) > x = c !! y !! x : collectDiagonal c (y+1) (x+1) | otherwise = [] part1 c = do let forwardXMAS = map (length . filter (List.isPrefixOf "XMAS") . List.tails) $ c let backwardXMAS = map (length . filter (List.isPrefixOf "XMAS") . List.tails . reverse) $ c let downwardXMAS = map (length . filter (List.isPrefixOf "XMAS") . List.tails ) . List.transpose $ c let upwardXMAS = map (length . filter (List.isPrefixOf "XMAS") . List.tails . reverse ) . List.transpose $ c let leftSideDiagonals = map (\ y -> collectDiagonal c y 0) [0..length c] let leftTopDiagonals = map (\ x -> collectDiagonal c 0 x) [1..(length . List.head $ c)] let leftDiagonals = leftSideDiagonals ++ leftTopDiagonals let rightSideDiagonals = map (\ y -> collectDiagonal (map List.reverse c) y 0) [0..length c] let rightTopDiagonals = map (\ x -> collectDiagonal (map List.reverse c) 0 x) [1..(length . List.head $ c)] let rightDiagonals = rightSideDiagonals ++ rightTopDiagonals let diagonals = leftDiagonals ++ rightDiagonals let diagonalXMAS = map (length . filter (List.isPrefixOf "XMAS") . List.tails) $ diagonals let reverseDiagonalXMAS = map (length . filter (List.isPrefixOf "XMAS") . List.tails . reverse) $ diagonals print . sum $ [sum forwardXMAS, sum backwardXMAS, sum downwardXMAS, sum upwardXMAS, sum diagonalXMAS, sum reverseDiagonalXMAS] return () getBlock h w c y x = map (take w . drop x) . take h . drop y $ c isXBlock b = do let diagonal1 = collectDiagonal b 0 0 let diagonal2 = collectDiagonal (map List.reverse b) 0 0 diagonal1 `elem` ["SAM", "MAS"] && diagonal2 `elem` ["SAM", "MAS"] part2 c = do let lineBlocks = List.map (getBlock 3 3 c) [0..length c - 1] let groupedBlocks = List.map (flip List.map [0..(length . head $ c) - 1]) lineBlocks print . sum . map (length . filter isXBlock) $ groupedBlocks return () main = do c <- lines <$> getContents part1 c part2 c return ()
Nim
Could be done more elegantly, but I haven’t bothered yet.
proc solve(input: string): AOCSolution[int, int] = var lines = input.splitLines() block p1: # horiz for line in lines: for i in 0..line.high-3: if line[i..i+3] in ["XMAS", "SAMX"]: inc result.part1 for y in 0..lines.high-3: #vert for x in 0..lines[0].high: let word = collect(for y in y..y+3: lines[y][x]) if word in [@"XMAS", @"SAMX"]: inc result.part1 #diag \ for x in 0..lines[0].high-3: let word = collect(for d in 0..3: lines[y+d][x+d]) if word in [@"XMAS", @"SAMX"]: inc result.part1 #diag / for x in 3..lines[0].high: let word = collect(for d in 0..3: lines[y+d][x-d]) if word in [@"XMAS", @"SAMX"]: inc result.part1 block p2: for y in 0..lines.high-2: for x in 0..lines[0].high-2: let diagNW = collect(for d in 0..2: lines[y+d][x+d]) let diagNE = collect(for d in 0..2: lines[y+d][x+2-d]) if diagNW in [@"MAS", @"SAM"] and diagNE in [@"MAS", @"SAM"]: inc result.part2
I tried to think of some clever LINQ to do this one, but was blanking entirely.
So naïve search it is.
C#
string wordsearch = ""; int width; int height; public void Input(IEnumerable<string> lines) { wordsearch = string.Join("", lines); height = lines.Count(); width = lines.First().Length; } public void Part1() { int words = 0; for (int y = 0; y < height; y++) for (int x = 0; x < width; x++) words += SearchFrom(x, y); Console.WriteLine($"Words: {words}"); } public void Part2() { int words = 0; for (int y = 1; y < height - 1; y++) for (int x = 1; x < width - 1; x++) words += SearchCross(x, y); Console.WriteLine($"Crosses: {words}"); } public int SearchFrom(int x, int y) { char at = wordsearch[y * width + x]; if (at != 'X') return 0; int words = 0; for (int ydir = -1; ydir <= 1; ++ydir) for (int xdir = -1; xdir <= 1; ++xdir) { if (xdir == 0 && ydir == 0) continue; if (SearchWord(x, y, xdir, ydir)) words++; } return words; } private readonly string word = "XMAS"; public bool SearchWord(int x, int y, int xdir, int ydir) { int wordit = 0; while (true) { char at = wordsearch[y * width + x]; if (at != word[wordit]) return false; if (wordit == word.Length - 1) return true; wordit++; x += xdir; y += ydir; if (x < 0 || y < 0 || x >= width || y >= height) return false; } } public int SearchCross(int x, int y) { if (x == 0 || y == 0 || x == width - 1 || y == width - 1) return 0; char at = wordsearch[y * width + x]; if (at != 'A') return 0; int found = 0; for (int ydir = -1; ydir <= 1; ++ydir) for (int xdir = -1; xdir <= 1; ++xdir) { if (xdir == 0 || ydir == 0) continue; if (wordsearch[(y + ydir) * width + (x + xdir)] != 'M') continue; if (wordsearch[(y - ydir) * width + (x - xdir)] != 'S') continue; found++; } if (found == 2) return 1; return 0; }
I haven’t quite started yet, and this one does feel like a busy work kinda problem. I was wondering if I could write something to rotate the board and do the search, but I think that might be not worth the effort
C#
public class Day04 : Solver { private int width, height; private char[,] data; public void Presolve(string input) { var lines = input.Trim().Split("\n").ToList(); height = lines.Count; width = lines[0].Length; data = new char[height, width]; for (int i = 0; i < height; i++) { for (int j = 0; j < width; j++) { data[i, j] = lines[i][j]; } } } private static readonly string word = "XMAS"; public string SolveFirst() { int counter = 0; for (int start_i = 0; start_i < height; start_i++) { for (int start_j = 0; start_j < width; start_j++) { if (data[start_i, start_j] != word[0]) continue; for (int di = -1; di <= 1; di++) { for (int dj = -1; dj <= 1; dj++) { if (di == 0 && dj == 0) continue; int end_i = start_i + di * (word.Length - 1); int end_j = start_j + dj * (word.Length - 1); if (end_i < 0 || end_j < 0 || end_i >= height || end_j >= width) continue; for (int k = 1; k < word.Length; k++) { if (data[start_i + di * k, start_j + dj * k] != word[k]) break; if (k == word.Length - 1) counter++; } } } } } return counter.ToString(); } public string SolveSecond() { int counter = 0; for (int start_i = 1; start_i < height - 1; start_i++) { for (int start_j = 1; start_j < width - 1; start_j++) { if (data[start_i, start_j] != 'A') continue; int even_mas_starts = 0; for (int di = -1; di <= 1; di++) { for (int dj = -1; dj <= 1; dj++) { if (di == 0 && dj == 0) continue; if ((di + dj) % 2 != 0) continue; if (data[start_i + di, start_j + dj] != 'M') continue; if (data[start_i - di, start_j - dj] != 'S') continue; even_mas_starts++; } } if (even_mas_starts == 2) counter++; } } return counter.ToString(); } }