Day 7: Bridge Repair
Megathread guidelines
- Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
- You can send code in code blocks by using three backticks, the code, and then three backticks or use something such as https://topaz.github.io/paste/ if you prefer sending it through a URL
FAQ
- What is this?: Here is a post with a large amount of details: https://programming.dev/post/6637268
- Where do I participate?: https://adventofcode.com/
- Is there a leaderboard for the community?: We have a programming.dev leaderboard with the info on how to join in this post: https://programming.dev/post/6631465
Python
Takes ~5.3s on my machine to get both outputs. Not sure how to optimize it any further other than running the math in threads? Took me longer than it should have to realize a lot of unnecessary math could be cut if the running total becomes greater than the target while doing the math. Also very happy to see that none of the inputs caused the recursive function to hit Python’s max stack depth.
Code
import argparse import os class Calibrations: def __init__(self, target, operators) -> None: self.operators = operators self.target = target self.target_found = False def do_math(self, numbers, operation) -> int: if operation == "+": return numbers[0] + numbers[1] elif operation == "*": return numbers[0] * numbers[1] elif operation == "||": return int(str(numbers[0]) + str(numbers[1])) def all_options(self, numbers, last) -> int: if len(numbers) < 1: return last for j in self.operators: # If we found our target already, abort # If the last value is greater than the target, abort if self.target_found or last > self.target: return total = self.all_options( numbers[1:], self.do_math((last, numbers[0]), j) ) if total == self.target: self.target_found = True def process_line(self, line) -> int: numbers = [int(x) for x in line.split(":")[1].strip().split()] self.all_options(numbers[1:], numbers[0]) if self.target_found: return self.target return 0 def main() -> None: path = os.path.dirname(os.path.abspath(__file__)) parser = argparse.ArgumentParser(description="Bridge Repair") parser.add_argument("filename", help="Path to the input file") args = parser.parse_args() sum_of_valid = [0, 0] with open(f"{path}/{args.filename}", "r") as f: for line in f: line = line.strip() target = int(line.split(":")[0]) for idx, ops in enumerate([["+", "*"], ["+", "*", "||"]]): c = Calibrations(target, ops) found = c.process_line(line) sum_of_valid[idx] += found if found: break for i in range(0, 2): part = i + 1 print( "The sum of valid calibrations for Part " + f"{part} is {sum(sum_of_valid[:part])}" ) if __name__ == "__main__": main()
https://github.com/stevenviola/advent-of-code-2024
If you havent already done so, doing it in the form of “tree search”, the code completes in the blink of an eye (though on a high end cpu 11th Gen Intel® Core™ i7-11800H @ 2.30GHz). posted the code below
Thanks! yup, I figured there would be a way. You’re right, much faster, on my machine with your code, this is the speed:
$ time python3 day7.py 4555081946288 227921760109726 real 0m0.171s
I’ll have to take a look to understand how that works to be better.
I posted my solution here and found my way to finish 30 milliseconds faster.(~100ms for his, and ~66 ms for mine) However, as I noted I stop prematurely sometimes. Which seems to work with my given input. but here is the one that makes sure it gets to the end of the list of integers:
code