Day 23: LAN Party

Megathread guidelines

  • Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
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FAQ

  • lwhjp@lemmy.sdf.org
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    5 hours ago

    The solution for part two could now be used for part one as well but then I would have to rewrite part 1 .-.

    I initially thought that, but now I reconsider I’m not so sure. Isn’t it possible to have a 3-member clique overlapping two larger ones? In other words, there could be more than one way to partition the graph into completely connected components. Which means my solution to part 2 is technically incorrect. Bummer.

    • VegOwOtenks@lemmy.world
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      1 hour ago

      There probably are multiple ways to partition the graph. I haven’t applied any optimizations and my program checks members of already detected groups again, would that yield all possible partitions because I choose all the possible starting points for a k-clique?