Day 2: Cube Conundrum

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FAQ

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  • Cyno
    3·
    1 year ago

    Was pretty simple in Python with a regex to get the game number, and then the count of color. for part 2 instead of returning true/false whether the game is valid, you just max the count per color. No traps like in the first one, that I’ve seen, so it was surprisingly easy

    def process_game(line: str):
    game_id = int(re.findall(r'game (\d+)*', line)[0])

    colon_idx = line.index(":")
    draws = line[colon_idx+1:].split(";")
    # print(draws)
    
    if is_game_valid(draws):
        # print("Game %d is possible"%game_id)
        return game_id
    return 0

            
def is_game_valid(draws: list):
    for draw in draws:
        red = get_nr_of_in_draw(draw, 'red')
        if red > MAX_RED:
            return False
        
        green = get_nr_of_in_draw(draw, 'green')
        if green > MAX_GREEN:
            return False
        
        blue = get_nr_of_in_draw(draw, 'blue')
        if blue > MAX_BLUE:
            return False    
    return True
        
            
def get_nr_of_in_draw(draw: str, color: str):
    if color in draw:
        nr = re.findall(r'(\d+) '+color, draw)
        return int(nr[0])
    return 0


# f = open("input.txt", "r")
f = open("input_real.txt", "r")
lines = f.readlines()
sum = 0
for line in lines:
    sum += process_game(line.strip().lower())
print("Answer: %d"%sum)