Day 11: Plutonian Pebbles
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FAQ
- What is this?: Here is a post with a large amount of details: https://programming.dev/post/6637268
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Rust
Part 2 is solved with recursion and a cache, which is indexed by stone numbers and remaining rounds and maps to the previously calculated expansion size. In my case, the cache only grew to 139320 entries, which is quite reasonable given the size of the result.
Solution
use std::collections::HashMap; fn parse(input: String) -> Vec<u64> { input .split_whitespace() .map(|w| w.parse().unwrap()) .collect() } fn part1(input: String) { let mut stones = parse(input); for _ in 0..25 { let mut new_stones = Vec::with_capacity(stones.len()); for s in &stones { match s { 0 => new_stones.push(1), n => { let digits = s.ilog10() + 1; if digits % 2 == 0 { let cutoff = 10u64.pow(digits / 2); new_stones.push(n / cutoff); new_stones.push(n % cutoff); } else { new_stones.push(n * 2024) } } } } stones = new_stones; } println!("{}", stones.len()); } fn expansion(s: u64, rounds: u32, cache: &mut HashMap<(u64, u32), u64>) -> u64 { // Recursion anchor if rounds == 0 { return 1; } // Calculation is already cached if let Some(res) = cache.get(&(s, rounds)) { return *res; } // Recurse let res = match s { 0 => expansion(1, rounds - 1, cache), n => { let digits = s.ilog10() + 1; if digits % 2 == 0 { let cutoff = 10u64.pow(digits / 2); expansion(n / cutoff, rounds - 1, cache) + expansion(n % cutoff, rounds - 1, cache) } else { expansion(n * 2024, rounds - 1, cache) } } }; // Save in cache cache.insert((s, rounds), res); res } fn part2(input: String) { let stones = parse(input); let mut cache = HashMap::new(); let sum: u64 = stones.iter().map(|s| expansion(*s, 75, &mut cache)).sum(); println!("{sum}"); } util::aoc_main!();
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