Day 17: Chronospatial Computer
Megathread guidelines
- Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
- You can send code in code blocks by using three backticks, the code, and then three backticks or use something such as https://topaz.github.io/paste/ if you prefer sending it through a URL
FAQ
- What is this?: Here is a post with a large amount of details: https://programming.dev/post/6637268
- Where do I participate?: https://adventofcode.com/
- Is there a leaderboard for the community?: We have a programming.dev leaderboard with the info on how to join in this post: https://programming.dev/post/6631465
C#
This one is mostly thanks to reading @mykl@[email protected]’s code to understand WTF was going on for part 2, and then once I understood the basics, finally got to solving it myself. Instructions were read in as
long
because I didn’t want to deal withint
vs.long
all the time.using System.Collections.Immutable; using System.Diagnostics; using Common; namespace Day17; static class Program { public record State(long A, long B, long C, int InstPtr, ImmutableList<long> Output); static void Main() { var start = Stopwatch.GetTimestamp(); var (sampleReg, sampleInst) = ReceiveInput("sample.txt"); var (inputReg, inputInst) = ReceiveInput("input.txt"); Console.WriteLine($"Part 1 sample: {Part1(sampleReg, sampleInst)}"); Console.WriteLine($"Part 1 input: {Part1(inputReg, inputInst)}"); (sampleReg, sampleInst) = ReceiveInput("sample2.txt"); Console.WriteLine($"Part 2 sample: {Part2(sampleReg, sampleInst)}"); Console.WriteLine($"Part 2 input: {Part2(inputReg, inputInst)}"); Console.WriteLine($"That took about {Stopwatch.GetElapsedTime(start)}"); } static object Part1(State state, ImmutableArray<long> instructions) => Execute(instructions, state).Output.StringifyAndJoin(","); static object Part2(State state, ImmutableArray<long> instructions) => RecursiveSolve(instructions, state with { A = 0 }, []).First(); static IEnumerable<long> RecursiveSolve(ImmutableArray<long> instructions, State state, ImmutableList<long> soFar) => (soFar.Count == instructions.Length) ? [state.A] : Enumerable.Range(0, 8) .Select(a => state with { A = (state.A << 3) + a }) .Where(newState => newState.A != state.A) .Select(newState => new { newState, Execute(instructions, newState).Output, }) .Where(states => states.Output.SequenceEqual(instructions.TakeLast(states.Output.Count))) .SelectMany(states => RecursiveSolve(instructions, states.newState, states.Output)); static State Execute(ImmutableArray<long> instructions, State state) { while (state.InstPtr < instructions.Length) { var opcode = instructions[state.InstPtr]; var operand = instructions[state.InstPtr + 1]; state = Operations[opcode](state, operand); } return state; } static long ComboOperand(long operand, State state) => operand switch { >= 0 and <= 3 => operand, 4 => state.A, 5 => state.B, 6 => state.C, _ => throw new Exception("Invalid operand."), }; static long Adv(long op, State state) => state.A / (long)Math.Pow(2, ComboOperand(op, state)); static readonly Func<State, long, State>[] Operations = [ (s, op) => s with { InstPtr = s.InstPtr + 2, A = Adv(op, s) }, (s, op) => s with { InstPtr = s.InstPtr + 2, B = s.B ^ op }, (s, op) => s with { InstPtr = s.InstPtr + 2, B = ComboOperand(op, s) % 8 }, (s, op) => s with { InstPtr = (s.A == 0) ? (s.InstPtr + 2) : (op <= int.MaxValue) ? (int)op : throw new ArithmeticException("Integer overflow!") }, (s, _) => s with { InstPtr = s.InstPtr + 2, B = s.B ^ s.C }, (s, op) => s with { InstPtr = s.InstPtr + 2, Output = s.Output.Add(ComboOperand(op, s) % 8) }, (s, op) => s with { InstPtr = s.InstPtr + 2, B = Adv(op, s) }, (s, op) => s with { InstPtr = s.InstPtr + 2, C = Adv(op, s) }, ]; static (State, ImmutableArray<long> instructions) ReceiveInput(string file) { var input = File.ReadAllLines(file); return ( new State( long.Parse(input[0].Substring("Register A: ".Length)), long.Parse(input[1].Substring("Register B: ".Length)), long.Parse(input[2].Substring("Register C: ".Length)), 0, []), input[4].Substring("Program: ".Length) .Split(",") .Select(long.Parse) .ToImmutableArray() ); } }
C
Was looking forward to a VM! Really took my leisure for part 1, writing a disassembler, tracing, all pretty.
Part 2 reminded me of 2021 day 24 where we also had to reverse an input. It’s been on my mind recently and I was thinking if there would be a way to backfeed an output through a program, yielding a representation like: “the input plus 3498 is a multiple of 40, and divisible by a number that’s 5 mod 8” (considering lossy functions like modulo and integer division).
Today’s input didn’t lend itself to that, however, but analysing it having the solution ‘click’ was very satisfying.
Code
#include "common.h" #define MEMZ 32 #define OUTZ 32 #define BUFZ 64 enum { ADV, BXL, BST, JNZ, BXC, OUT, BDV, CDV }; struct vm { int64_t mem[MEMZ]; int nm, pc; int64_t out[OUTZ]; int no; int64_t a,b,c; } vm; /* returns 0 if halted, 1 otherwise */ static int step(void) { int64_t op, ar, ac; /* operator, lit. arg, combo arg */ assert(vm.pc >= 0); assert(vm.pc+2 <= MEMZ); if (vm.pc >= vm.nm) return 0; op = vm.mem[vm.pc++]; ar = vm.mem[vm.pc++]; ac = ar==4 ? vm.a : ar==5 ? vm.b : ar==6 ? vm.c : ar; switch (op) { case ADV: vm.a = vm.a >> ac; break; case BDV: vm.b = vm.a >> ac; break; case CDV: vm.c = vm.a >> ac; break; case BXL: vm.b = vm.b ^ ar; break; case BXC: vm.b = vm.b ^ vm.c; break; case BST: vm.b = ac % 8; break; case JNZ: if (vm.a) vm.pc = ar; break; case OUT: assert(vm.no < OUTZ); vm.out[vm.no++] = ac%8; break; default: assert(!"invalid opcode"); return 0; } return 1; } static int64_t recur_p2(int64_t a0, int pos) { int64_t a, i; /* * The code in the input uses up to 7 low bits of the A register * to produce a single number, then chops off the low 3 bits and * continues. * * That means bits above the current triplet influence what * number it generates, but bits below don't. To generate a * desired sequence then, we append, not prepend, candidate * triplets. * * We may end up in a situation where, given the prefix found * for the numbers so far, no triplet yields the desired next * number. Then we have to backtrack and find another prefix, * hence the recursion. */ if (pos >= vm.nm) return a0 >> 3; for (i=0; i<8; i++) { vm.a=a= a0+i; vm.b=vm.c=vm.pc=vm.no= 0; while (step() && !vm.no) ; if (vm.no && vm.out[0] == vm.mem[vm.nm-pos-1]) if ((a = recur_p2(a << 3, pos+1))) return a; } return 0; } int main(int argc, char **argv) { char b[BUFZ], *tok, *rest; int i; if (argc > 1) DISCARD(freopen(argv[1], "r", stdin)); fgets(b, BUFZ, stdin); sscanf(b, "Register A: %lld", &vm.a); fgets(b, BUFZ, stdin); sscanf(b, "Register B: %lld", &vm.b); fgets(b, BUFZ, stdin); sscanf(b, "Register C: %lld", &vm.c); fgets(b, BUFZ, stdin); assert(vm.b == 0); /* assumption for part 2 */ assert(vm.c == 0); rest = fgets(b, sizeof(b), stdin); strsep(&rest, ":"); while ((tok = strsep(&rest, ","))) { assert(vm.nm < MEMZ); vm.mem[vm.nm++] = atoll(tok); } while (step()) ; for (i=0; i<vm.no; i++) printf(i ? ",%lld" : "17: %lld", vm.out[i]); printf(" %lld\n", recur_p2(0, 0)); return 0; }
Haskell
Runs in 10 ms. I was stuck for most of the day on the bdv and cdv instructions, as I didn’t read that the numerator was still register A. Once I got past that, it was pretty straight forward.
Code
import Control.Monad.State.Lazy import Data.Bits (xor) import Data.List (isSuffixOf) import qualified Data.Vector as V data Instr = ADV Int | BXL Int | BST Int | JNZ Int | BXC | OUT Int | BDV Int | CDV Int type Machine = (Int, Int, Int, Int, V.Vector Int) parse :: String -> Machine parse s = let (la : lb : lc : _ : lp : _) = lines s [a, b, c] = map (read . drop 12) [la, lb, lc] p = V.fromList $ read $ ('[' :) $ (++ "]") $ drop 9 lp in (a, b, c, 0, p) getA, getB, getC, getIP :: State Machine Int getA = gets $ \(a, _, _, _ , _) -> a getB = gets $ \(_, b, _, _ , _) -> b getC = gets $ \(_, _, c, _ , _) -> c getIP = gets $ \(_, _, _, ip, _) -> ip setA, setB, setC, setIP :: Int -> State Machine () setA a = modify $ \(_, b, c, ip, p) -> (a, b, c, ip, p) setB b = modify $ \(a, _, c, ip, p) -> (a, b, c, ip, p) setC c = modify $ \(a, b, _, ip, p) -> (a, b, c, ip, p) setIP ip = modify $ \(a, b, c, _ , p) -> (a, b, c, ip, p) incIP :: State Machine () incIP = getIP >>= (setIP . succ) getMem :: State Machine (Maybe Int) getMem = gets (\(_, _, _, ip, p) -> p V.!? ip) <* incIP getCombo :: State Machine (Maybe Int) getCombo = do n <- getMem case n of Just 4 -> Just <$> getA Just 5 -> Just <$> getB Just 6 -> Just <$> getC Just n | n <= 3 -> return $ Just n _ -> return Nothing getInstr :: State Machine (Maybe Instr) getInstr = do opcode <- getMem case opcode of Just 0 -> fmap ADV <$> getCombo Just 1 -> fmap BXL <$> getMem Just 2 -> fmap BST <$> getCombo Just 3 -> fmap JNZ <$> getMem Just 4 -> fmap (const BXC) <$> getMem Just 5 -> fmap OUT <$> getCombo Just 6 -> fmap BDV <$> getCombo Just 7 -> fmap CDV <$> getCombo _ -> return Nothing execInstr :: Instr -> State Machine (Maybe Int) execInstr (ADV n) = (getA >>= (setA . (`div` (2^n)))) *> return Nothing execInstr (BDV n) = (getA >>= (setB . (`div` (2^n)))) *> return Nothing execInstr (CDV n) = (getA >>= (setC . (`div` (2^n)))) *> return Nothing execInstr (BXL n) = (getB >>= (setB . xor n)) *> return Nothing execInstr (BST n) = setB (n `mod` 8) *> return Nothing execInstr (JNZ n) = do a <- getA case a of 0 -> return () _ -> setIP n return Nothing execInstr BXC = ((xor <$> getB <*> getC) >>= setB) *> return Nothing execInstr (OUT n) = return $ Just $ n `mod` 8 run :: State Machine [Int] run = do mInstr <- getInstr case mInstr of Nothing -> return [] Just instr -> do mOut <- execInstr instr case mOut of Nothing -> run Just n -> (n :) <$> run solve2 :: Machine -> Int solve2 machine@(_, _, _, _, p') = head [a | x <- [1 .. 7], a <- go [x]] where p = V.toList p' go as = let a = foldl ((+) . (* 8)) 0 as in case evalState (setA a *> run) machine of ns | ns == p -> [a] | ns `isSuffixOf` p -> concatMap go [as ++ [a] | a <- [0 .. 7]] | otherwise -> [] main :: IO () main = do machine@(_, _, _, _, p) <- parse <$> getContents putStrLn $ init $ tail $ show $ evalState run machine print $ solve2 machine
I did the same thing for BDV and CDV, wild that none of the test cases covered them.
Dart
Part one was an exercise in building a simple OpCode machine. Part two was trickier. It was clear that the
a
register was repeatedly being divided by 8, and testing a few values showed that each 3-bits of the initial value defined one entry in the output, so I built a recursive routine that brute-forced each one in turn. Only <1ms to run though, so not that brutal.(It’s worth pointing out that at some stages multiple 3-bit values gave rise to the required value, causing a failure to resolve later on if not checked.)
(edit: for-loop in
buildQuine
now avoids using a0
for the initial triplet, as this should not be a valid value, and if it turns out to generate the required digit of the quine, you will get an infinite recursion. Thanks to SteveDinn for bringing this to my attention.)import 'dart:math'; import 'package:collection/collection.dart'; import 'package:more/more.dart'; var prog = <int>[]; typedef State = (int, int, int); State parse(List<String> lines) { var regs = lines.takeTo('').map((e) => int.parse(e.split(' ').last)).toList(); var (a, b, c) = (regs[0], regs[1], regs[2]); prog = lines.last.split(' ').last.split(',').map(int.parse).toList(); return (a, b, c); } List<int> runProg(State rec) { var (int a, int b, int c) = rec; combo(int v) => switch (v) { 4 => a, 5 => b, 6 => c, _ => v }; var output = <int>[], pc = 0; while (pc < prog.length) { var code = prog[pc], arg = prog[pc + 1]; var _ = switch (code) { 0 => a ~/= pow(2, combo(arg)), 1 => b ^= arg, 2 => b = combo(arg) % 8, 3 => (a != 0) ? (pc = arg - 2) : 0, 4 => b ^= c, //ignores arg 5 => output.add(combo(arg) % 8), 6 => b = a ~/ pow(2, combo(arg)), 7 => c = a ~/ pow(2, combo(arg)), _ => 0 }; pc += 2; } return output; } Function eq = const ListEquality().equals; Iterable<int> buildQuine(State rec, List<int> quine, [top = false]) sync* { var (int a0, int b0, int c0) = rec; if (top) a0 = 0; if (quine.length == prog.length) { yield a0; return; } for (var a in (top ? 1 : 0).to(8)) { var newState = (a0 * 8 + a, b0, c0); var newQuine = runProg(newState); if (eq(prog.slice(prog.length - newQuine.length), newQuine)) { yield* buildQuine(newState, newQuine); } } } part1(List<String> lines) => runProg(parse(lines)).join(','); part2(List<String> lines) => buildQuine(parse(lines), [], true).first;
I’m confused reading the
buildQuine()
method. It reads to me that when you call it from the top level withtop = true
,A0
will be set to 0, and then when we get to the 0 to 8 loop, the ‘A’ register will be0 * 8 + 0
for the first iteration, and then recurse withtop = false
, but witha0
still ending up 0, causing infinite recursion.Am I missing something?
I got it to work with a check that avoids the recursion if the last state’s A register value is the same as the new state’s value.
Oh, good catch. That’s certainly the case if an initial value of 0 correctly generates the required value of the quine. As I’d already started running some code against the live data that’s what I tested against, and so it’s only when I just tested it against the example data that I saw the problem.
I have changed the for-loop to read
for (var a in (top ? 1 : 0).to(8))
for maximum terseness :-)That still works for the example and my live data, and I don’t think there should be a valid solution that relies on the first triplet being 0. Thanks for your reply!
Rust
First part was straightforward (the divisions are actually just right shifts), second part not so much. I made some assumptions about the input program, namely that in the end register 8 is divided by 8, then an output is made, then everything starts from the beginning again (if a isn’t 0). I found that the output always depends on at most 10 bits of a, so I ran through all 10-bit numbers and grouped them by the first generated output. At that point it’s just a matter of chaining these 10-bit numbers from the correct groups so that they overlap on 7 bits. The other 3 bits are consumed each round.
Solution
use rustc_hash::FxHashMap; fn parse(input: &str) -> Option<Program> { let mut lines = input.lines(); let a = lines.next()?.split_once(": ")?.1.parse().ok()?; let b = lines.next()?.split_once(": ")?.1.parse().ok()?; let c = lines.next()?.split_once(": ")?.1.parse().ok()?; lines.next()?; let program = lines .next()? .split_once(": ")? .1 .split(',') .map(|s| s.parse()) .collect::<Result<Vec<u8>, _>>() .ok()?; Some(Program { a, b, c, out: vec![], program, ip: 0, }) } #[derive(Debug, Clone, Default)] struct Program { a: u64, b: u64, c: u64, out: Vec<u8>, program: Vec<u8>, ip: usize, } impl Program { fn run(&mut self) { while self.step() {} } // Returns true if a step was taken, false if it halted fn step(&mut self) -> bool { let Some(&[opcode, operand]) = &self.program.get(self.ip..self.ip + 2) else { return false; }; self.ip += 2; match opcode { 0 => self.adv(self.combo(operand)), 1 => self.bxl(operand), 2 => self.bst(self.combo(operand)), 3 => self.jnz(operand), 4 => self.bxc(), 5 => self.out(self.combo(operand)), 6 => self.bdv(self.combo(operand)), 7 => self.cdv(self.combo(operand)), _ => panic!(), } true } fn combo(&self, operand: u8) -> u64 { match operand { 0..=3 => operand as u64, 4 => self.a, 5 => self.b, 6 => self.c, _ => unreachable!(), } } fn adv(&mut self, x: u64) { self.a >>= x } fn bxl(&mut self, x: u8) { self.b ^= x as u64 } fn bst(&mut self, x: u64) { self.b = x % 8 } fn jnz(&mut self, x: u8) { if self.a != 0 { self.ip = x as usize } } fn bxc(&mut self) { self.b ^= self.c } fn out(&mut self, x: u64) { self.out.push((x % 8) as u8) } fn bdv(&mut self, x: u64) { self.b = self.a >> x } fn cdv(&mut self, x: u64) { self.c = self.a >> x } } fn part1(input: String) { let mut program = parse(&input).unwrap(); program.run(); if let Some(e) = program.out.first() { print!("{e}") } for e in program.out.iter().skip(1) { print!(",{e}") } println!() } // Some assumptions on the input: // * There is exactly one jump instruction at the end of the program, jumping to 0 // * Right before that, an output is generated // * Right before that, register a is shifted right by 3: adv(3) // // Each output depends on at most 10 bits of a (it is used with a shift of at most 7). // Therefore we look at all 10-bit a's and group them by the first number that is output. // Then we just need to combine these generators into a chain that fits together. fn number_generators(mut program: Program) -> [Vec<u16>; 8] { let mut out = [const { vec![] }; 8]; for a in 1..(1 << 10) { program.a = a as u64; program.out.clear(); program.ip = 0; program.run(); let &output = program.out.first().unwrap(); out[output as usize].push(a); } out } fn part2(input: String) { let mut program = parse(&input).unwrap(); let generators = number_generators(program.clone()); let output = program.program.clone(); // a_candidates maps from 7-bit required prefixes to the lower bits of a that // generate the required numbers so far. let mut a_candidates: FxHashMap<u8, u64> = generators[output[0] as usize] .iter() .rev() // Collects the values for each prefix .map(|&a| ((a >> 3) as u8, a as u64 % 8)) .collect(); let len = output.len(); for (i, x) in output.iter().enumerate().skip(1) { let mut next_candidates = FxHashMap::default(); for (prefix, val) in generators[*x as usize] .iter() .filter(|&a| { // Take only short candidates in the end to ensure that not too many numbers are generated let max_bits = (len - i) * 3; (*a as u64) < (1u64 << max_bits) }) // Only use generators that match any required prefix .filter(|&a| a_candidates.contains_key(&((a % (1 << 7)) as u8))) .map(|&a| { let prefix = (a >> 3) as u8; let val = a as u64 % 8; let prev = a_candidates[&((a % (1 << 7)) as u8)]; (prefix, (val << (i * 3)) | prev) }) { // Only insert first (smallest) encountered value next_candidates.entry(prefix).or_insert(val); } a_candidates = next_candidates; } println!("{}", a_candidates[&0]); // Verify result program.a = a_candidates[&0]; program.run(); assert_eq!(program.out, program.program); } util::aoc_main!();
Also on github
Your code helped me find my bug, thanks.
Wild that all the examples can be passed with an incorrect
cdv
instruction, I didnt read the last part properly and assumed it was C /= operand. :(
Haskell
Part 2 was tricky, I tried executing the algorithm backwards, which worked fine for the example but not with the input program, because it uses one-way functions .-. Then I tried to write an algorithm that would try all valid combinations of powers of 8 and but I failed, I then did it by hand.
Solution Codeblock
import Control.Arrow import Data.Bits import qualified Data.Char as Char import qualified Data.List as List replace c r c' = if c' == c then r else c' parse :: String -> ([Integer], [Int]) parse = map (replace ',' ' ') >>> filter ((Char.isDigit &&& Char.isSpace) >>> uncurry (||)) >>> words >>> splitAt 3 >>> (map read *** map read) type InstructionPointer = Int adv = 0 bxl = 1 bst = 2 jnz = 3 bxc = 4 out = 5 bdv = 6 cdv = 7 lookupCombo _ 0 = 0 lookupCombo _ 1 = 1 lookupCombo _ 2 = 2 lookupCombo _ 3 = 3 lookupCombo regs 4 = regs !! 0 lookupCombo regs 5 = regs !! 1 lookupCombo regs 6 = regs !! 2 lookupCombo regs 7 = error "Invalid operand" execute :: InstructionPointer -> [Integer] -> [Int] -> [Int] execute ip regs@(regA:regB:regC:[]) ops | ip >= length ops = [] | instruction == adv = execute (ip + 2) [regA `div` (2 ^ comboValue), regB, regC] ops | instruction == bxl = execute (ip + 2) [regA, xor regB (toInteger operand), regC] ops | instruction == bst = execute (ip + 2) [regA, comboValue `mod` 8, regC] ops | instruction == jnz && regA == 0 = execute (ip + 2) regs ops | instruction == jnz && regA /= 0 = execute operand regs ops | instruction == bxc = execute (ip + 2) [regA, xor regB regC, regC] ops | instruction == out = (fromIntegral comboValue) `mod` 8 : execute (ip + 2) regs ops | instruction == bdv = execute (ip + 2) [regA, regA `div` (2 ^ comboValue), regC] ops | instruction == cdv = execute (ip + 2) [regA, regB, regA `div` (2 ^ comboValue)] ops where (instruction, operand) = (ops !! ip, ops !! (succ ip)) comboValue = lookupCombo regs operand part1 = uncurry (execute 0) >>> List.map show >>> List.intercalate "," valid i t n = ((n `div` (8^i)) `mod` 8) `xor` 7 `xor` (n `div` (4*(8^i))) == t part2 = const 247839653009594 main = getContents >>= print . (part1 &&& part2) . parse ```haskell
Haskell
Woah, that was suddenly a hard one: several tricky things combined. I’m not a big fan of the kind of problems like part 2 today, but eh - you can’t please everyone.
Solution
import Control.Monad import Control.Monad.RWS import Data.Bits import Data.Foldable import Data.List import Data.List.Split import Data.Vector (Vector) import Data.Vector qualified as Vector type Machine = RWS (Vector Int) [Int] (Int, Int, Int) readInput :: String -> ((Int, Int, Int), Vector Int) readInput s = let (regs, _ : [prog]) = break null $ lines s in ( let [a, b, c] = map (read . last . words) regs in (a, b, c), let [_, s] = words prog in Vector.fromList $ map read $ splitOn "," s ) stepMachine :: Int -> Machine Int stepMachine ip = do opcode <- asks (Vector.! ip) operand <- asks (Vector.! (ip + 1)) (a, b, c) <- get let combo = [0, 1, 2, 3, a, b, c, undefined] !! operand ip' = ip + 2 adv = a `div` (2 ^ combo) store 'A' v = modify (\(_, b, c) -> (v, b, c)) store 'B' v = modify (\(a, _, c) -> (a, v, c)) store 'C' v = modify (\(a, b, _) -> (a, b, v)) case opcode of 0 -> store 'A' adv >> return ip' 1 -> store 'B' (b `xor` operand) >> return ip' 2 -> store 'B' (combo .&. 7) >> return ip' 3 -> return $ if a == 0 then ip' else operand 4 -> store 'B' (b `xor` c) >> return ip' 5 -> tell [combo .&. 7] >> return ip' 6 -> store 'B' adv >> return ip' 7 -> store 'C' adv >> return ip' part1 (regs, prog) = let (a, s, w) = runRWS (go 0) prog regs in intercalate "," $ map show w where go ip = when (ip < Vector.length prog) $ stepMachine ip >>= go part2 (_, prog) = minimum $ foldM go 0 $ reverse $ toList prog where go a d = do b <- [0 .. 7] let a' = (a `shiftL` 3) .|. b b1 = b `xor` 5 b2 = b1 `xor` (a' `shiftR` b1) b3 = b2 `xor` 6 guard $ b3 .&. 7 == d return a' main = do input <- readInput <$> readFile "input17" putStrLn $ part1 input print $ part2 input
C#
public class Day17 : Solver { private List<int> program; private long a, b, c; public void Presolve(string input) { var data = input.Trim().Split("\n"); a = long.Parse(Regex.Match(data[0], @"\d+").Value); b = long.Parse(Regex.Match(data[1], @"\d+").Value); c = long.Parse(Regex.Match(data[2], @"\d+").Value); program = data[4].Split(" ")[1].Split(",").Select(int.Parse).ToList(); } public string SolveFirst() => String.Join(',', Execute(a, b, c)); private List<int> Execute(long a, long b, long c) { List<int> output = []; Func<long, long> combo = operand => operand switch { <= 3 => operand, 4 => a, 5 => b, 6 => c, _ => throw new InvalidDataException(), }; int ip = 0; while (ip < program.Count - 1) { switch (program[ip]) { case 0: a = a >> (int)combo(program[ip + 1]); break; case 1: b = b ^ program[ip + 1]; break; case 2: b = combo(program[ip + 1]) % 8; break; case 3: if (a != 0) { ip = program[ip + 1]; continue; } break; case 4: b = b ^ c; break; case 5: output.Add((int)(combo(program[ip + 1]) % 8)); break; case 6: b = a >> (int)combo(program[ip + 1]); break; case 7: c = a >> (int)combo(program[ip + 1]); break; } ip += 2; } return output; } public string SolveSecond() { Dictionary<int, List<(int, int, int)>> mapping = []; for (int start_a = 0; start_a < 512; start_a++) { var output = Execute(start_a, b, c); mapping.TryAdd(output[0], []); mapping[output[0]].Add((start_a / 64, start_a / 8 % 8, start_a % 8)); } List<List<(int, int, int)>> possible_codes = [.. program.Select(b => mapping[b])]; possible_codes.Reverse(); List<int>? solution = SolvePossibleCodes(possible_codes, null); solution?.Reverse(); long result = 0; foreach (var code in solution!) { result = (result << 3) | code; } return result.ToString(); } private List<int>? SolvePossibleCodes(List<List<(int, int, int)>> possible_codes, (int, int)? allowed_start) { if (possible_codes.Count == 0) return []; foreach (var (high, mid, low) in possible_codes[0]) { if (allowed_start is null || allowed_start.Value.Item1 == high && allowed_start.Value.Item2 == mid) { var tail = SolvePossibleCodes(possible_codes[1..], (mid, low)); if (tail is null) continue; tail.Add(low); if (allowed_start is null) { tail.Add(mid); tail.Add(high); } return tail; } } return null; } }